Question
Question: How many spectral lines are seen for hydrogen atoms when electrons jump from \( n_2 = 5\; \) to \( n...
How many spectral lines are seen for hydrogen atoms when electrons jump from n2=5 to n1=1 in a visible region?
Solution
Hint : In order to solve this question we must know few basic information like what is meant by spectral lines. Spectral series are said to be the set of wavelengths arranged in a sequential fashion which characterizes light or any electromagnetic radiation emitted by the energised atoms.
Complete Step By Step Answer:
Hydrogen atom is said to be the simplest atomic system found in nature, thus it produces the simplest of the spectral series.
When electrons de-excite from higher energy level ( n2 ) to lower energy level ( n1 ) in atomic sample, then number of spectral line observed in the spectrum is given by the formula;
Total no of the spectral lines=2(n2−n1)(n2−n1+1)
Since it is given in the question that in hydrogen atom electron jumps from n2=5 to n1=1
Therefore the total no of the spectral line is found to be;
Total no of the spectral lines=2(5−1)(5−1+1)
Total no of the spectral lines=10
So, the ten lines are;
5→4,5→3,5→2,5→1,4→3,4→2,4→1,3→2,3→1,2→1 are possible in this case.
Balmer series is displayed when electron transition takes place from higher energy states ( nh=3,4,5,6,7,… ) to nl=2 energy state.
For Balmer series, nl=2 and nh=3,4,5
Thus,
5→2,4→2,3→2 it shows three lines lie in the visible region.
Hence the final answer is three spectral lines lie in the visible region for the hydrogen atom when electrons jump from n2=5 to n1=1 in the visible region.
Note :
All the wavelength of the Balmer series falls in the visible part of the electromagnetic spectrum( 400nm to 740nm ). Other series are lyman series, paschen series, bracket series, pfund series, Humphreys series. The series is observed at a higher wavelength. The spectral lines are extremely faint and widely spread out. They correspond to highly rare atomic events.