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Question: How many spectral lines are seen for hydrogen atoms when electrons jump from \( n_2 = 5\; \) to \( n...

How many spectral lines are seen for hydrogen atoms when electrons jump from n2=5  n_2 = 5\; to n1=1  n_1 = 1\; in a visible region?

Explanation

Solution

Hint : In order to solve this question we must know few basic information like what is meant by spectral lines. Spectral series are said to be the set of wavelengths arranged in a sequential fashion which characterizes light or any electromagnetic radiation emitted by the energised atoms.

Complete Step By Step Answer:
Hydrogen atom is said to be the simplest atomic system found in nature, thus it produces the simplest of the spectral series.
When electrons de-excite from higher energy level ( n2n_2 ) to lower energy level ( n1n_1 ) in atomic sample, then number of spectral line observed in the spectrum is given by the formula;
Total no of the spectral lines  =(n2n1)(n2n1+1)2Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {n_2 - n_1} \right)\left( {n_2 - n_1 + 1} \right)}}{2}
Since it is given in the question that in hydrogen atom electron jumps from n2=5  n_2 = 5\; to n1=1  n_1 = 1\;
Therefore the total no of the spectral line is found to be;
Total no of the spectral lines  =(51)(51+1)2Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = \dfrac{{\left( {5 - 1} \right)\left( {5 - 1 + 1} \right)}}{2}
Total no of the spectral lines  =10Total{\text{ }}no{\text{ }}of{\text{ }}the{\text{ }}spectral{\text{ }}lines\; = 10
So, the ten lines are;
54,53,52,51,43,42,41,32,31,21  5 \to 4,5 \to 3,5 \to 2,5 \to 1,4 \to 3,4 \to 2,4 \to 1,3 \to 2,3 \to 1,2 \to 1\; are possible in this case.
Balmer series is displayed when electron transition takes place from higher energy states ( nh=3,4,5,6,7,{{\mathbf{n}}_{\mathbf{h}}} = {\mathbf{3}},{\mathbf{4}},{\mathbf{5}},{\mathbf{6}},{\mathbf{7}}, \ldots ) to nl=2{{\mathbf{n}}_{\mathbf{l}}} = {\mathbf{2}} energy state.
For Balmer series, nl=2{n_l} = 2 and nh=3,4,5{n_h} = 3,4,5
Thus,
52,42,32  5 \to 2,4 \to 2,3 \to 2\; it shows three lines lie in the visible region.
Hence the final answer is three spectral lines lie in the visible region for the hydrogen atom when electrons jump from n2=5  n_2 = 5\; to n1=1  n_1 = 1\; in the visible region.

Note :
All the wavelength of the Balmer series falls in the visible part of the electromagnetic spectrum( 400nm to 740nm400nm{\text{ }}to{\text{ }}740nm ). Other series are lyman series, paschen series, bracket series, pfund series, Humphreys series. The series is observed at a higher wavelength. The spectral lines are extremely faint and widely spread out. They correspond to highly rare atomic events.