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Question

Chemistry Question on Some basic concepts of chemistry

How many seconds are there in 33 days?

A

259200s259200\, s

B

172800s172800\, s

C

24800s24800\, s

D

72000s72000\, s

Answer

259200s259200\, s

Explanation

Solution

Seconds in 33 days can be calculated as 33 days ×24h1day×60min1h×60s1min\times\frac{24\, h }{1 \,day} \times \frac{60\, min }{1\, h}\times\frac{ 60 \,s}{1 \,min} =3×24×60×60s= 3\times 24\times 60\times 60\, s =259200s = 259200\, s