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Question

Question: How many positive numbers \[x\] satisfy the equation \[\cos \left( {97x} \right) = x\] ? A) \[1\] ...

How many positive numbers xx satisfy the equation cos(97x)=x\cos \left( {97x} \right) = x ?
A) 11
B) 1515
C) 3131
D) 4949

Explanation

Solution

In the above question, we are given a trigonometric equation cos(97x)=x\cos \left( {97x} \right) = x . We have to find the number of positive values for which the given equation cos(97x)=x\cos \left( {97x} \right) = x is satisfied. In order to approach the solution, first we have to check the period of cos(97x)\cos \left( {97x} \right) . As we know that the period of the standard trigonometric function of cosine, i.e. cosx\cos x is 2π2\pi , hence the period of cos(97x)\cos \left( {97x} \right) will be given by 2π97\dfrac{{2\pi }}{{97}}.

Complete step by step answer:
The trigonometric function is cos(97x)=x\cos \left( {97x} \right) = x .
We have to find how many positive values of xx satisfy the above given equation.
Since the period of cosines function cosx\cos x is 2π2\pi .
Hence, the period of cos(97x)\cos \left( {97x} \right) is 2π97\dfrac{{2\pi }}{{97}} .
The range of cosine function, cosx\cos x is [1,1]\left[ { - 1,1} \right] .
The range of cosine function, cosx\cos x for only positive values is [0,1]\left[ {0,1} \right] .
Now, since the period of cos(97x)\cos \left( {97x} \right) is 2π97\dfrac{{2\pi }}{{97}} ,
Therefore in between the interval [0,1]\left[ {0,1} \right] , the functions repeats itself, i.e. makes oscillations for about the number of times equal to
12π97\Rightarrow \dfrac{1}{{\dfrac{{2\pi }}{{97}}}}
That is,
972×722\Rightarrow \dfrac{{97}}{2} \times \dfrac{7}{{22}}
Hence,
15.438\Rightarrow 15.438
These are 1515and almost a half times.
Also in each period, the two functions, cos(97x)\cos \left( {97x} \right) and xx meet twice.
Therefore,
15.438×2\Rightarrow 15.438 \times 2
That gives,
30.876\Rightarrow 30.876
Hence, there is almost one more cycle completed which might have one more value of xx .
Therefore, there are total possible positive values of xx equal to the number of times,
30+1\Rightarrow 30 + 1
That is,
31\Rightarrow 31
That is the required number of positive values of xx .
Therefore, there are 3131 positive numbers xx that satisfy the equation cos(97x)=x\cos \left( {97x} \right) = x.

Hence, the correct option is (C).

Note:
We can also confirm our answer by the graphical method.
Let us suppose two functions xx and cos(97x)\cos \left( {97x} \right) .
Now after plotting their graphs we can see that there are 3131intersections in the interval [0,1]\left[ {0,1} \right] of both the functions.
The graph is given below.