Question
Question: How many numbers of two digits are divisible by \(3\) ?...
How many numbers of two digits are divisible by 3 ?
Solution
Hint: Select the lowest and highest two digit terms divisible by 3. To see whether the series is an A.P or not. Then if it is in A.P solve it by taking the nth term of the A.P. Find the value of n. You will get the answer.
We use ten digits in the way we count. Sometimes we use one digit to represent a number and sometimes we use more. In this lesson, you'll learn how many digits are in any given numeral, and recognize a digit when you see it. You will also begin learning about place value.
This is the numeral: 51.These are the digits in that numeral: 5 and 1. The numeral has two digits because two symbols, or digits, make up the numeral 51. What about this numeral ? 452. This numeral has three digits: 4,5 and 2.
That 7 is a special kind of symbol. It's called a digit. We have ten digits we use to make up all numerals. A numeral is a number written down. These digits are 0,1,2,3,4,5,6,7,8 and 9. That's it! You can make any numeral you want out of those ten digits.
Just like a red light means 'stop', a 7 means 'seven'. It's a single symbol that represents a numeral. Yes, just like this is a symbol to stop.
We know, first two digit number divisible by 3 is 12 and the last two digit number divisible by 3 is 99. Thus, we get 12,15,......,99.
So the lowest two digit number divisible by 3 is 12.
Highest two digit number divisible by 3 is 99.
So we can see the difference between the numbers that are divisible by 3, is 3.
So the above series is in A.P.
We have to find it in terms of n.
And herea=12,d=3,an=99
Thus, the nthterm of A.P is :
an=a+(n−1)d
Where,
a=First-term
d= Common difference
n= number of terms
an=nthterm
So now applying the formula for 99, we get,
99=12+(n−1)3
Simplifying further we get,
99−12=(n−1)387=3n−390=3nn=30
So we get n=30.
Therefore, the number of two digits divisible by 3 are 30.
Note: Read the question properly. Also, we should know the lowest and highest two digit terms divisible by 3. So the concepts related to A.P should be clear. Here we have used the concept of A.P that is we have used nth term of A.P which is an=a+(n−1)d.