Question

How many numbers of 6 digits can be formed from the digits of the number 112233 ?

• A. 30
• B. 60
• C. 90
• D. 120

Answer 1

Answer: (C)

90

Answer 2

Here the digits repeat as: 1 = 2 times, 2 = 2 times and 3 = 2 times Thus the total no. of the permutation $= \frac{( 2 + 2 + 2)! }{2! 2! 2!} = \frac{6 \times5 \times 4 \times 3 \times 2 \times 1}{2 \times 2 \times 2} = 90$