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Question

Question: How many numbers lying between \( 99 \) and \( 1000 \) can be made from the digits \( 2,3,7,0,8,6 \)...

How many numbers lying between 9999 and 10001000 can be made from the digits 2,3,7,0,8,62,3,7,0,8,6 when the digits occur only once in each number?
A)100A)100
B)90B)90
C)120C)120
D)80D)80

Explanation

Solution

First, from the given that we have numbers between 9999 and 10001000 . These numbers need to be made from the given digits 2,3,7,0,8,62,3,7,0,8,6 .
Condition is given as digits occurring only once in each number means digits without repetition in the process of finding the numbers between 9999 and 10001000 .
Between the numbers, 99,100099,1000 will not be included.

Complete step by step answer:
Since from the given that we have numbers between 9999 and 10001000 . There are only three digits numbers because 99,100099,1000 will not be included. Thus, we reframe the given question from the numbers 100100 to 999999 .
Now we have to find the number of ways made from the given digits 2,3,7,0,8,62,3,7,0,8,6 for the numbers 100100 to 999999 .
Place Hundred:
For the place hundred, the starting digit will not be zero (because if it's zero then it will be placed ten) and thus we get the non-zero numbers 2,3,7,8,62,3,7,8,6 are the number of ways.
Hence, we get a total 55 ways can be made in a hundred places.
Place Ten:
For place ten, we have a total 66 possible ways, but the condition is given as digits occurring only once in each number means digits without repetition.
So, in the place of a hundred occurrences (that one number) will not be repeated.
Thus, we have 4+14 + 1 (in hundred places not occurred numbers plus the number zero) ways
Hence, we have a total 55 ways that can be made in tenth place.
Unit place:
Again, for the unit place, the possible ways are 66 .
But in hundred places occurred digit and also in the tenth place occurred digits are not be repeated and thus we have 62=46 - 2 = 4 ways for the unit place.
Therefore, in total we have 5×5×4=1005 \times 5 \times 4 = 100 ways.

So, the correct answer is “Option A”.

Note: Suppose the given question is about lying from 9999 and 10001000 be made from the digits 2,3,7,0,8,62,3,7,0,8,6 then we also need to find the place values for two digits occurring 9999 and four digits occurring 10001000 .
Repetition means once previously used numbers can be repeated and digits occur only once in each number means no repetition and the number used will not be repeated.