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Question: How many numbers greater than \[40,000\] can be formed by using the digits \[1,2,3,4\] and \[5\]. If...

How many numbers greater than 40,00040,000 can be formed by using the digits 1,2,3,41,2,3,4 and 55. If each is used only once in a number?
1. 24
2. 78
3. 32
4. 48

Explanation

Solution

Initially fix the position with 44 or greater than 44 to make a number greater than 40,000\,40,000 and solve the rest of the part by the method of permutation to find the number of ways.

Complete step by step answer:
Given: Five digits 1,2,3,4\,1,2,3,4 and 55 are given by which we have to find how many numbers greater than40,000\,40,000 can be formed.
Make a box of the five section to understand the concept easily

Initially, we have to fix a digit at 1st position and first position can be filled by two digits out of 5 digits (excluded 1,2,31,2,3)
We can’t place 1or2or31\,or\,2\,or\,3 at the first position because it is mandatory to form a no. greater than 40,000\,40,000.
So 1st position can be filled =2=2 ways.
Formula for permutation =npr={}^{n}{{p}_{r}}
The rest of the positions can be filled in =4p4=4!={}^{4}{{p}_{4}}=4! ways.
The number of ways first position ×\,\,\times the no. of ways the rest of positions can be filled
=2×4p4=\,2\times {}^{4}{{p}_{4}}
=2×4!=2\times 4!
Further simplifying we get:
=2×4×3×2×1=2\times 4\times 3\times 2\times 1
=48=48\,Ways.
Hence48\,48\,numbers greater than40,000\,40,000 can be formed from the digits1,2,3,4\,1,2,3,4 and5\,5.
So, the correct answer is “Option 4”.

Note: After finding out the possibility of the first position we will apply the concept of permutation. If the question has 5\,5 comes two times then we will divide by 2!2! with possible ways in the rest of the positions and if a no. comes 3\,3 times then it must be divided by 3!3! and so on. So, in this way we can solve similar types of problems.