Question

How many numbers divisible by 5 and lying between 3000 and 4000 can be formed from the digits 1, 2, 3, 4, 5, 6 (repetition is not allowed).

• A. $\frac{n + r - 1}{r}$
• B. $5P_{2}$
• C. $4P_{2}$
• D. $6P_{3}$

Answer 1

Answer: (C)

$4P_{2}$

Answer 2

To be divisible by 5, the digit 5 must be at unit place, so now to be between 3000 and 4000, 3 must be at thousand place. Hence the required number of ways $=^{4} ⥂ P_{2}$.