Question

How many numbers consisting of 5 digits can be formed in which the digits 3, 4 and 7 are used only once and the digit 5 is used twice.

• A. 30
• B. 60
• C. 45
• D. 90

Answer 1

Answer: (B)

60

Answer 2

Required number of ways are $\frac{5!}{2!} = 60$.