Question

How many number of moles of nitrogen will be present in $2.24L$of nitrogen gas at STP?

• A. $9.9$
• B. $0.099$
• C. $0.001$
• D. $1.00$

Answer 1

Answer: (B)

$0.099$

Answer 2

: PV = nRT

P = atm, T = 273 K, V = $2.24L$

$R = 0.0821LatmK^{- 1}mol^{- 1}$

$n = \frac{1 \times 2.24}{0.0821 \times 273} = 0.099$