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Question: How many number of electrons are present in a particle which carries a charge of \(5.5 \times 10^{- ...

How many number of electrons are present in a particle which carries a charge of 5.5×10−165.5 \times 10^{- 16}C?

A

3432

B

1560

C

8240

D

2432

Answer

3432

Explanation

Solution

: Charge carried by one electron =1.6022×10−19C= 1.6022 \times 10^{- 19}C

Electrons present in 5.5×10−16C5.5 \times 10^{- 16}C

=5.5×10−161.6022×10−19=3432= \frac{5.5 \times 10^{- 16}}{1.6022 \times 10^{- 19}} = 3432