Question

How many moles of silicon are in $1.67 \times {10^{24}}$ Si atoms?

Answer 1

As we know, the mole can be utilized to relate masses of substances to the number of atoms in that. This is a simple method of deciding the amount of one substance that can react with a given measure of another substance. From the moles of a substance, one can likewise locate the number of molecules in a sample and the other way around.

Complete step-by-step answer:
The extension among particles and moles is Avogadro's number,$6.022 \times {10^{23}}$. Avogadro's number is ordinarily dimensionless, however, when it characterizes the mole, it very well may be communicated as $6.022 \times {10^{23}}$ rudimentary substances/mol. This structure shows the part of Avogadro's number as a transformation factor between the number of substances and the number of moles. In this manner, given the relationship of $1mole =$ $6.022 \times {10^{23}}$ atoms, changing over among moles and molecules of a substance turns into a straightforward dimensional analysis problem.

It was discovered that for each 1 mole of a substance, $6.022 \times {10^{23}}$ atoms were in that substance. In other words, there is $6.022 \times {10^{23}}$ particles/mole. Therefore, let us look at the atoms of silicon given as $1.67 \times {10^{24}}$molecules. Now we can consider determining the number of moles by dividing it with Avogadro’s number. $\therefore \dfrac{{1.67 \times {{10}^{24}}}}{{6.022 \times {{10}^{23}}}} = 2.77moles$. So, there will be $2.77moles$of silicon.

Note: The molar mass is the mass of a given chemical component or chemical compound (g) partitioned by the measure of substance (mole). The molar mass of a compound can be determined by adding the standard atomic masses (in g/mole) of the constituent particles. Molar mass fills in as an extension between the mass of material and the number of moles since it is beyond the realm of imagination to expect to quantify the number of moles directly.