Question

How many moles of Pt may be deposited on the cathode when $0.80F$of electricity is passed through a $1.0M$ solution of $Pt^{4 +}?$

• A. $0.1mol$
• B. $0.2mol$
• C. $0.4mol$
• D. $0.6mol$

Answer 1

Answer: (B)

$0.2mol$

Answer 2

$Pt^{4 +} + 4e^{-} \rightarrow Pt$

4 moles of electricity of 4 F of electricity is required to deposit 1 mole of Pt.

$0.80F$ of electricity will deposit

$\frac{1}{4} \times 0.80 = 0.20mol$