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Chemistry Question on Some basic concepts of chemistry

How many moles of magnesium phosphate Mg3(PO4)2Mg_3(PO_4)_2 will contains 0.250.25 mole of oxygen atoms:

A

0.020.02

B

3.125 × 10−23.125 \,\times\, 10^{-2}

C

1.25 × 10−21.25 \,\times\, 10^{-2}

D

2.5 × 10−22.5 \,\times\, 10^{-2}

Answer

3.125 × 10−23.125 \,\times\, 10^{-2}

Explanation

Solution

88 mole of OO atoms =1= 1 mole Mg3(PO4)2Mg_3(PO_4)_2 0.250.25 mole of O-atom =1 × 0.258= \frac{1\,\times\,0.25}{8} =3.125 × 10−2= 3.125 \,\times\, 10^{-2} mole of Mg3(PO4)2.Mg_{3}\left(PO_{4}\right)_{2}.