Solveeit Logo
Login

Question

Chemistry Question on Mole concept and Molar Masses

How many moles of magnesium phosphate, Mg3(po4)2Mg_{3} \left(po_{4}\right)_{2} will contain 0.25 mole of oxygen atoms ?

A

0.02

B

3.125×10−23.125\times10^{-2}

C

1.25×10−21.25\times10^{-2}

D

2.5×10−22.5\times10^{-2}

Answer

3.125×10−23.125\times10^{-2}

Explanation

Solution

Mg3(po4)2;moleM g_{3} \left(po_{4}\right)_{2} ; mole 8 moles of O-atom are contained by 1 mole Mg3(po4)2⋅M g_{3} \left(po_{4}\right)_{2\cdot} Hence, 0.25 moles of O-atom=18×0.25\frac{1}{8}\times0.25 =3.125×10−2=3.125\times10^{-2}