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Question

Chemistry Question on Some basic concepts of chemistry

How many moles of electron weight one kilogram :

A

6.023×10236.023 \times 10^{23}

B

19.108×1023 \frac{1}{9.108 }\times10^{23}

C

6.0239.108×1054 \frac{6.023}{9.108 } \times 10^{54}

D

19.108×6.023×108 \frac{1}{9.108 \times 6.023}\times10^{8}

Answer

19.108×6.023×108 \frac{1}{9.108 \times 6.023}\times10^{8}

Explanation

Solution

Mass of an electron =9.108×10−31 kg=9.108 \times 10^{-31} \,kg

Mass of one mole of electron

=(9.108×10−31×6.023×1023) kg=\left(9.108 \times 10^{-31} \times 6.023 \times 10^{23}\right)\, kg

Then, number of mole of electron in 1 kg1 \,kg

=19.108×6.023×10−8=\frac{1}{9.108 \times 6.023 \times 10^{-8}}

=19.08×6.023×108=\frac{1}{9.08 \times 6.023} \times 10^{8} mole of e−e^{-}