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Question

Chemistry Question on Some basic concepts of chemistry

How many moles of electron weighs 1 kg?

A

6.023×10236.023 \times {10}^{23}

B

19.108×1031 \frac{1}{9.108} \times {10}^{31}

C

6.0239.108×1054\frac{ 6.023}{9.108} \times {10}^{54}

D

19.108×6.023×108 \frac{1}{9.108 \times 6.023 } \times {10}^8

Answer

19.108×6.023×108 \frac{1}{9.108 \times 6.023 } \times {10}^8

Explanation

Solution

Mass of an electron = 9.108 ×10−31kg \times {10}^{-31} kg
∵\because 9.108 ×10−31kg=1.0electron\times {10} ^{-31} kg = 1.0 electron \therefore 1kg=19.108×10−31electrons=10319.108×16.023×10231kg = \frac{1}{9.108 \times {10}^{-31}} electrons = \frac{ {10}^{31}}{9.108} \times \frac{1}{ 6.023 \times {10}^{23}}
       =19.108×6.023×108\, \, \, \, \, \, \, = \frac{1}{ 9.108 \times 6.023} \times {10}^ 8 mole of electrons