Question

How many moles of $Ba_3(PO_4)_2$ will be formed by the reaction of $5$ moles of $BaCl_2$ and $3$ moles of $Na_3(PO_4)$.

Answer 1

$3\; BaCl_2 + 2\;Na_3 PO_4 → Ba_3(PO_4)_2 + 6\;NaCl$
$5$ $mole$ $3$ $mole$
$\text{Moles of}$ $Ba_3(PO_4)_2 = \frac{5}{3}$