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Question: How many moles are present in 165 g of Manganese?...

How many moles are present in 165 g of Manganese?

Explanation

Solution

To solve this question, we first need to understand what is a mole. Mole is the SI unit of measurement and is used to determine the amount of a substance. A mole of any substance has exactly 6.022×10236.022\times {{10}^{23}} particles which can be ions, atoms, electrons, or molecules.

Complete step by step answer:
We know that if one mole of a substance is present, it has exactly the Avogadro number (NA)({{N}_{A}}) of particles.
NA=6.022×1023{{N}_{A}}=6.022\times {{10}^{23}}
Now, the mass of a sample can be given by the sum of the mass of all the particles in it.
So, we can say that the mass of one mole of a compound is equivalent to the mass of all the particles contained in one mole of a substance i.e., 6.022×10236.022\times {{10}^{23}} particles.
The mass of one mole of a substance is known as the molar mass of that substance. Its SI base unit is kg/mol but it is usually expressed in g/mol. It is a bulk property of a substance, not a molecular property.
Now, the molar mass of a sample is given by the mass of the sample substance divided by the number of moles of the substance present in the sample.
M=mnM=\dfrac{m}{n}
So, the number of moles in a given sample can be given by
n=mMn=\dfrac{m}{M}
Where n is the number of moles,
m is the mass of the substance given (in grams), and
M is the molar mass of the substance (in g/mol).
We know that the molar mass of Manganese (Mn) is 54.938 g/mol.
It is given to us that the mass of the sample substance is 165 grams.
So, the number of moles of the substance in the sample is

n=165g54.938g/mol n3.003mol  n=\dfrac{165g}{54.938g/mol} \\\ n\cong 3.003mol \\\

Hence there are approximately 3.003 moles in a sample of 165 grams of Manganese (Mn).

Note: It must be noted that in 2019, the SI base unit of molar mass was redefined. According to the new definition, the molar mass constant is
Mu=0.99999999965×103kg/mol{{M}_{u}}=0.99999999965\times {{10}^{-3}}kg/mol
And not 1×103kg/mol1\times {{10}^{-3}}kg/mol.
But since the change is so insignificant, for practical purposes, the molar mass of an element is still considered to be equivalent to the atomic mass of the element.