Question
Question: How many molecules of sucrose, \({{\text{C}}_{{\text{12}}}}{{\text{H}}_{{\text{22}}}}{{\text{O}}_{{\...
How many molecules of sucrose, C12H22O11 are there in 454grams of sucrose(C12H22O11)?
Solution
The mole concept is used to determine the amount of the substance which is obtained by taking the ratio of the mass of the substance to the molecular mass of the substance.
One mole of the substance contains the Avogadro’s numbers of the particles that are atoms, ions, or molecules of the substance.
Avogadro’s number is represented as NA. The value of Avogadro’s number is 6.023×1023molecules.
Complete solution:
Here, the molecular weight of the sucrose given is 342.30g/mol and the weight of the sucrose is 454grams.
We have to determine the first moles of the sucrose in 454grams as follows:
moles = Molecularweightweight
Substitute, 342.30g/mol for molecular weight and 454grams for weight.
moles = 342.30g/mol454g
moles = 1.3263mol
Thus, the moles of the sucrose in 454gramsare 1.3263mol.
Now, determine the molecules of the sucrose in 454gramsas follows:
As we know that one mole of the substance contains Avogadro’s numbers of molecules.
1mol = NA = 6.023×1023molecules
1.3263mol = 1mol1.3263mol×6.023×1023molecules
1.3263mol = 7.988×1023molecules
Thus, the molecules of sucrose in 454gramsare 7.988×1023.
Note: Molecular weight is the average mass of the molecules and it differs from molecule to molecule. In the case of the atom, it is called atomic mass while in the case of the molecular mass it is calculated by taking the sum of the atomic masses of all the atoms in the molecule.
The SI unit of the molecular weight is gram per mole. Its unit itself indicates the ratio of the mass of the substance to the molar molecular mass of the substance.