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Question

Question: How many molecules are there in \(4.00\) mol of glucose?...

How many molecules are there in 4.004.00 mol of glucose?

Explanation

Solution

We need to remember that glucose is one of the carbohydrates. It is monohydrate in nature, it has an aldehyde group. The molecular formula of glucose is C6H12O6{C_6}{H_{12}}{O_6} . The mole is one of the chemical units used to measure the molecules. It is mainly used to express the quantity of individual atoms. One mole means the amount of substance, which contains elementary particles. Here we considered atoms in 12g12g of carbon- 1212 isotope. By using this mole concept, we find the number of atoms of the element and the number of molecules in the compound.
Formula used:
The number of molecules in the compound is equal to the product of the number of moles of the molecules and Avogadro’s number.
The Avogadro’s number is 6.022×10236.022 \times {\text{1}}{{\text{0}}^{{\text{23}}}}. It is represented by NA{N_A}.
Apply the numerical value of Avogadro’s number, we get the formula
Number of molecules= number of moles ×6.022×1023 \times 6.{\text{022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}

Complete step by step answer:
Given,
The number of moles in glucose molecule = 4.004.00 moles.
Calculate the number of molecules of glucose present in given moles,
Number of molecules= number of moles ×6.022×1023 \times 6.{\text{022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}
1mole of glucose = 1×6.022×10231{\text{mole of glucose = 1}} \times {\text{6}}{\text{.022}} \times {\text{1}}{{\text{0}}^{{\text{23}}}}
=6.022×1023= 6.022 \times {\text{1}}{{\text{0}}^{{\text{23}}}}
One mole of glucose having 6.022×10236.022 \times {\text{1}}{{\text{0}}^{{\text{23}}}} molecules of glucose.
4.004.00moles of glucose is calculated,
4.00mole of glucose = 4.00×  6.022 ×10234.00{\text{mole of glucose = 4}}{\text{.00}} \times \;{\text{6}}{\text{.022 }} \times {\text{1}}{{\text{0}}^{{\text{23}}}}
=24.088×1023= 24.088 \times {\text{1}}{{\text{0}}^{{\text{23}}}}
=2.4088×1024= 2.{\text{4088}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}
We round of the value,
=2.49×1024= 2.{\text{49}} \times {\text{1}}{{\text{0}}^{{\text{24}}}}
Hence, 4.004.00 moles of glucose having 2.49×10242.{\text{49}} \times {\text{1}}{{\text{0}}^{{\text{24}}}} molecules of glucose.

Note:
This mole unit plays an important role in chemical reaction. By using this mole only we concluded the reaction, how moving. Molar mass is the concept, the mass of an atom present in one mole of substance. Avogadro’s number doesn’t have any units. Avogadro’s number is named after Amedeo Avogadro. He is Italian scientist. He proposed the equal volume of all the gases molecules under the same condition of temperature and pressure contain equal numbers of molecules in the same substance. This is the reason for keeping his name for this number.