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Question: How many molecules are in a sample of water with a mass of \[44.99{\text{ }}grams\] ?...

How many molecules are in a sample of water with a mass of 44.99 grams44.99{\text{ }}grams ?

Explanation

Solution

Water is denoted with the symbols of H2O{H_2}O having the molecular mass 18 g/mol{\text{18 }}g/mol . A mole is defined as 6.02214076×10236.02214076 \times {10^{23}} of a chemical unit in the terms of ions, atoms, molecules, etc. A mole is a unit measurement for the amount of substance in the international system of units i.e., SI unit. A mole of a particle or a mole of a substance is defined as 6.02214076×10236.02214076 \times {10^{23}} of a chemical unit, that can be ions, atoms, molecules, etc. Originally it was defined as the number of atoms in 12 g12{\text{ }}g of carbon-12.

Complete step-by-step answer:
First, we need to calculate the number of moles of water;
As we know, the number of moles will be equal to the given mass divided by the molecular mass of a compound.
Hence, the formula will be as follows,
n=massmolarmassn\,\, = \,\,\dfrac{{mass}}{{molar\,mass}}
Where,
n=n\, = the amount in moles (mol)(mol)
Mass will be in the terms of  (g)\;(g)
Molar mass will be in the terms of   (g/mol)\;(g/mol)
Now, the given values are;
Mass of the water=44.99 grams = \,\,44.99{\text{ }}grams
Molar mass of the water = 18 g/mol{\text{ = }}\,\,{\text{18 }}g/mol
So, the number of moles of water will be,
n=44.99g18g/moln\,\, = \,\,\dfrac{{44.99\,g}}{{18\,g/mol}}
We get,
=2.5moles= \,2.5\,\,moles of water
Since a mole of any substances will be =6.02214076×1023 = \,6.02214076 \times {10^{23}} molecules
Therefore, a mole of water is having 6.02214076×10236.02214076 \times {10^{23}} molecules.
So, we have to multiply the moles with the Avogadro’s number to get the number of molecules.
Now, let’s calculate the number of molecules present in 44.99 grams44.99{\text{ }}grams of water
=6.022×1023mol1×2.50mol= \,6.022 \times {10^{23}}\,mo{l^{ - 1}}\, \times \,2.50\,mol
=15.04×1023= 15.04\, \times \,{10^{23}} molecules

Therefore, in 44.99 grams44.99{\text{ }}grams of water there is 15.04×102315.04\, \times \,{10^{23}} molecules

Note: In one mole of substance there contains an Avogadro’s number (NA{N_A} ) of atoms
So, the equation will be;
1mole=6.022×1023atoms1\,mole\, = \,6.022\, \times \,{10^{23}}\,atoms
Now let’s calculate for 11 atom;
So, we get;
1atom=16.022×1023moles1\,atom\, = \,\dfrac{1}{{6.022\, \times \,{{10}^{23}}}}\,moles
Therefore, the answer will be;
1atom=1.66×1024moles1\,atom\, = 1.66\, \times \,{10^{ - 24}}\,\,moles
One atom contains 1.66×10241.66\, \times \,{10^{ - 24}} number of moles