Question
Chemistry Question on Structure of atom
How many mole of electrons are required for the reduction of 1 mole of Cr3+ to Cr(s)?
A
1
B
6.022 x 1023
C
3
D
6
Answer
3
Explanation
Solution
The balanced reduction half-reaction for the reduction of Cr3+ to Cr(s) can be represented as Cr3+(aq) + 3e- → Cr(s)
From the balanced equation, we can see that 3 moles of electrons (3e-) are required to reduce 1 mole of Cr3+ to Cr(s).
Therefore, the correct answer is 3.