Question
Question: How many mL of 6.0 M HCl solution will provide 164 g of HCl?...
How many mL of 6.0 M HCl solution will provide 164 g of HCl?
Solution
Here, first we have to calculate the moles of HCl using the formula, Number of moles=MolarMassMass. Then, we have to calculate the volume of HCl solution using the formula of molarity.
Complete step by step answer:
Let’s calculate the moles of HCl first. The mass of HCl is given as 164 g . Now, we have to calculate the molar mass of HCl.
Molar mass of HCl=1+35.5=36.5gmol−1.
Now, we have to put the values of mass and molar mass of HCl in the formula of moles. So,
The number of moles of HCl=36.5gmol−1164gmol=4.49mol
So, the mole of HCl present in the solution is 4.49.
Now, we have to use the formula of molarity to calculate the volume of HCl solution. The formula of molarity is,
Molarity=Volumeofsolution(L)Molesofsolute
The molality of the HCl solution is given as 6.0 M and the moles of HCl is 4.49. So,
Volume of HCl solution=MolarityMoles of HCl
⇒Volume of HCl solution=64.49=0.748L
Now, we have to convert the volume in litre to mililitre.
0.748 L=0.748×1000=748mL
Hence, 748 mL of 6.0 M HCl solution will provide 164 g of HCl.
Additional Information:
Molarity is a way of expressing concentration of a solution. Molarity is defined as the number of moles of solute present in one litre solution.
Note: The mole or mol (abbreviation form) is the unit which measures the amount of substance present. A mole is the term that defines the number of carbon (C) atoms in 12 g of pure carbon. After so many years of experiment, it has been proved that a mole of anything contains 6.022×1023 representative particles.