Question
Question: How many ![](https://cdn.pureessence.tech/canvas_254.png?top_left_x=1563&top_left_y=618&width=300&he...
How many ions are present in 100 mL of 0.25M of NaCl solution
A
0.025×1023
B
1.505×1022
C
15×1022
D
2.5×1023
Answer
1.505×1022
Explanation
Solution
No. of moles of NaCl
=1000M×V=10000.25×100=0.025
NaCl→Na++Cl−
No. of moles of Na+ions =0.025
No of Na+ions = 0.025×6.023×1023=1.505×1022