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Question: How many litres of a \( 90\% \) acid solution must be added to \( 6 \) litres of a \( 15\% \) acid s...

How many litres of a 90%90\% acid solution must be added to 66 litres of a 15%15\% acid solution to obtain a 40%40\% acid solution?

Explanation

Solution

Any solution with a higher concentration of hydrogen ions than water is classified as acidic; solutions with a lower concentration of hydrogen ions than water is classified as basic or alkaline. All acidic solutions have pH less than 77 ,while bases have pH more than 77 . Acidity is measured on a scale known as pH, which sets water at 77 .

Complete answer:
Let the amount of litres of 90%90\% acid solution be xx .
From the question we know that the final solution will have 40%40\% acid solution and will be 6+x6 + x litres in volume.
Multiplying the volumes by solutions, where the percentage of acid concentration is in decimal form.
0.9x+0.15×6=0.4×6+x0.9x + 0.15 \times 6 = 0.4 \times 6 + x
Now after rearranging we get,
0.9x+0.9=2.4+0.4x0.9x + 0.9 = 2.4 + 0.4x
0.9x0.4x=2.40.90.9x - 0.4x = 2.4 - 0.9
0.5x=1.50.5x = 1.5
x=1.50.5x = \dfrac{{1.5}}{{0.5}}
x3x \Rightarrow 3
Hence, 33 litres of 90%90\% acid solution must be added to 66 litres of a 15%15\% acid solution to obtain a 40%40\% acid solution.

Additional Information:
The negative logarithm of H+{H^ + } ion concentration is used to calculate pH. As a result, the meaning of pH is justified as hydrogen power.

Note:
One of two methods is typically used to create acid solutions. One method is to dissolve a solid compound, such as citric acid, in water. The other method is to bubble gases through water, such as carbon dioxide (or HClHCl ). The material that dissolves in water is known as the solute in either case. The solvent is the liquid that dissolves the solute.