Question

How many liters are contained in 1.75 mol of ${{F}_{2}}$ gas at STP?

Answer 1

A mole of a substance or particle can be defined as containing exactly $6.02214076\times {{10}^{23}}$ particles which may be atoms, molecules or ions where $6.02214076\times {{10}^{23}}$ is known as the Avogadro’s number.

Complete step-by-step answer: Mole is generally represented by the symbol mol. It is generally described as the unit of measurement for the amount of substance in SI where SI stands for International System of units. It is defined on the basis of Avogadro’s number.
The calculation can be done according to Avogadro’s law which states that volume is directly proportional to the number of moles. This law also states that all ideal gases behave identically under the same conditions. Molar volume of any ideal gas at STP will be exactly equal to 22.4 L which is represented as ${{V}_{molar}}$ which represents that 1 mole of any gas at STP will occupy exactly 22.4 L volume, now we have to calculate the volume occupied by 1.75 mol of ${{F}_{2}}$ gas which can be calculated by the following formula:
$n=\dfrac{V}{{{V}_{molar}}}$; where n is number of moles which are given i.e. 1.75 and ${{V}_{molar}}$ which is 22.4 L as discussed then the value of V would be $V=n\times {{V}_{molar}}=1.75\times 22.4=39.2L$
Thus 39.2 liters are contained in 1.75 mol of ${{F}_{2}}$ gas at STP.

Note: STP stands for standard temperature and pressure and it can be defined as a temperature 273.15 K and an absolute pressure exactly equal to 100 kpa where temperature units K implies kelvin and pressure unit kpa represents kilo Pascal.