Solveeit Logo

Question

Mathematics Question on Mixtures and Allegations

How many kg of pure salt must be added to 30 kg of a 2% solution of salt and water to increase it to a 10% solution?

A

2232\frac{2}{3} kg

B

15 kg

C

3 kg

D

14 kg

Answer

2232\frac{2}{3} kg

Explanation

Solution

Let xx be the amount of pure salt to be added.
Initial salt in the solution 30kg×2%=0.6kg30 \, \text{kg} \times 2\% = 0.6 \, \text{kg}
Final salt in the solution 0.6+xkg0.6 + x \, \text{kg} of salt after adding xx kg of pure salt.
Final total weight 30+xkg30 + x \, \text{kg}
Now,
For a 10% solution

\Rightarrow\;$$\frac{0.6 + x}{30 + x} = 0.10
\Rightarrow\;$$0.6 + x = 0.10(30 + x)
\Rightarrow\;$$0.6 + x = 3 + 0.10x
\Rightarrow\;$$0.90x = 2.4
  \Rightarrow\; x=2.40.90=2.67kgx = \frac{2.4}{0.90} = 2.67 \, \text{kg}

The correct option is (A): 2232\frac{2}{3} or 2.672.67 kg