Question

How many integers in the set {100, 101, 102, ..., 999} have at least one digit repeated?
[This Question was asked as TITA]

• A. 252
• B. 254
• C. 262
• D. 264

Answer 1

Answer: (A)

252

Answer 2

The given set is a set of all three-digit numbers and the number of numbers in the set $=900$.
The number of three-digit numbers having no digits repeating = $9×9×8 = 648$
Required answer =$900-648=252$

So, the correct option is (A): $252$