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Question: How many half lives would it take for a sample of carbon-14 to be reduced to \({}^{1}/{}_{32}\)of it...

How many half lives would it take for a sample of carbon-14 to be reduced to 1/32{}^{1}/{}_{32}of its original mass?

Explanation

Solution

Half life is calculated for the compounds that undergo decay after completing their full life. Generally, calculated for isotopes of any element.

Complete step-by-step answer: We have been given a sample of carbon-14, reduced to 1/32{}^{1}/{}_{32}of its original mass. We have to calculate how many half lives it had taken to reach 1/32{}^{1}/{}_{32}of its original mass.
We have to apply a simple logic in this question. Half life is not to be calculated, only the number of half lives is to be determined. So, assuming half of the carbon-14 is decayed at half life of 12\dfrac{1}{2} we have to calculate, how many times of this half life is reduces the mass of carbon-14 by132\dfrac{1}{32}of the original mass. So, we have to keep reducing this 12\dfrac{1}{2} by half till we find 132\dfrac{1}{32}.
Half life of carbon-14 = 12ofitslife\dfrac{1}{2}\,of\,its\,life\,
Half of 12\dfrac{1}{2}is = 122\dfrac{\dfrac{1}{2}}{2} =14\dfrac{1}{4}\,\,\,\,\,
Now, half of 14\dfrac{1}{4}= 142\dfrac{\dfrac{1}{4}}{2}= 18\dfrac{1}{8}\,\,
Half, of 18\dfrac{1}{8}\,\,= 182\dfrac{\dfrac{1}{8}}{2}=116\dfrac{1}{16}\,\,
Half, of 116\dfrac{1}{16}\,\,= 1162\dfrac{\dfrac{1}{16}}{2}=132\dfrac{1}{32}\,\,
Thus, we have obtained the 132\dfrac{1}{32}\,\,of the original mass of carbon-14 in a total of 5 half lives.
Hence, 5 half lives will reduce the carbon-14 to 132\dfrac{1}{32}\,\,of the original mass.

Note: The half life of any element that undergoes decay is calculated using the formula, A(t)=A0(12)tt1/2A(t)={{A}_{0}}{{\left( \dfrac{1}{2} \right)}^{\dfrac{t}{{{t}_{{}^{1}/{}_{2}}}}}} , where A(t) is the amount of the remaining substance after decay, A0{{A}_{0}}is the initial amount of the substance, t is time taken for the decay, and t1/2{{t}_{{}^{1}/{}_{2}}} is the half life.