Question
Question: How many half lives would it take for a sample of carbon-14 to be reduced to \({}^{1}/{}_{32}\)of it...
How many half lives would it take for a sample of carbon-14 to be reduced to 1/32of its original mass?
Solution
Half life is calculated for the compounds that undergo decay after completing their full life. Generally, calculated for isotopes of any element.
Complete step-by-step answer: We have been given a sample of carbon-14, reduced to 1/32of its original mass. We have to calculate how many half lives it had taken to reach 1/32of its original mass.
We have to apply a simple logic in this question. Half life is not to be calculated, only the number of half lives is to be determined. So, assuming half of the carbon-14 is decayed at half life of 21 we have to calculate, how many times of this half life is reduces the mass of carbon-14 by321of the original mass. So, we have to keep reducing this 21 by half till we find 321.
Half life of carbon-14 = 21ofitslife
Half of 21is = 221 =41
Now, half of 41= 241= 81
Half, of 81= 281=161
Half, of 161= 2161=321
Thus, we have obtained the 321of the original mass of carbon-14 in a total of 5 half lives.
Hence, 5 half lives will reduce the carbon-14 to 321of the original mass.
Note: The half life of any element that undergoes decay is calculated using the formula, A(t)=A0(21)t1/2t , where A(t) is the amount of the remaining substance after decay, A0is the initial amount of the substance, t is time taken for the decay, and t1/2 is the half life.