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Question: How many grams of \(NaOH\) will be required to neutralize 12.2 g benzoic acid? (a) 12.2 g (b) 16...

How many grams of NaOHNaOH will be required to neutralize 12.2 g benzoic acid?
(a) 12.2 g
(b) 16g
(c) 40g
(d) 4g

Explanation

Solution

First find out the molecular mass of the NaOHNaOH and benzoic acid and from it first find how much NaOHNaOH is required to neutralize the 1g of the benzoic acid and then , use can easily find the NaOHNaOH used to neutralize the 12.2 g of benzoic acid.

Complete step by step solution:
NaOHNaOH is a strong base and has a pH of more than 7 and has a strong tendency to neutralize the other acids and such reactions are called the neutralization reactions.
Considering the given numerical;
In this, we have to find out the grams of NaOHNaOH required to neutralize the 12.2 g of benzoic acid.
So, as we know that, molecular mass of NaOH$$$=23+16+1\text{ =}40\text{ }g$$ Similarly, molecular mass of the benzoic acid i.e. \begin{aligned}
& {{C}{5}}{{H}{5}}COOH=12\times 5+5\times 1+12+16+16+1 \\
& \text{ = 60+5+12+33} \\
& \text{ = 110 }g \\
\end{aligned}Then,if110gofthebenzoicacidisneutralizedbythe=40gofthe Then ,if 110g of the benzoic acid is neutralized by the =40 g of theNaOHSimilarly,1gofthebenzoicacidwillbeneutralizedbythe= Similarly, 1g of the benzoic acid will be neutralized by the =\dfrac {40}{110}goftheg of theNaOHNowthen,12.2gofthebenzoicacidwillbeneutralizedbythe= Now then, 12.2g of the benzoic acid will be neutralized by the =\dfrac{40}{110}\times 12.2goftheg of theNaOH =$$\dfrac{488}{110}$$ g of theNaOH=4gofthe =4 g of theNaOHSo,thusinordertoneutralizethe12.2gofthebenzoicacid,weneedtotake4gofthe So, thus in order to neutralize the 12.2 g of the benzoic acid, we need to take 4 g of theNaOH$.

Hence, the option (d) is correct.

Note: NaOHNaOH is strong base and it turns red litmus blue indicating that it is basic in nature and is used in the manufacture of many detergents and soaps etc. and it is very soluble in water than in the non-polar solvent like the alcohol etc.