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Question: How many grams of NaOH are present in 250 mL of \(0.5 M\) NaOH solution...

How many grams of NaOH are present in 250 mL of 0.5M0.5 M NaOH solution

A

7.32g7.32 g

B

C

D

0.5 g

Answer

Explanation

Solution

No. of moles of NaOH

=M×V1000=0.25×2501000=0.125= \frac { \mathrm { M } \times \mathrm { V } } { 1000 } = \frac { 0.25 \times 250 } { 1000 } = 0.125

Mass of NaOH =40×0.125=5 g= 40 \times 0.125 = 5 \mathrm {~g}