Question

How many grams of iron are in 21.6 g of iron (III) oxide?

Answer 1

This question can be solved using the mole concept. Mole is the SI unit of measurement and is used to determine the amount of a substance. The molecular formula of iron (III) oxide is $F{{e}_{2}}{{O}_{3}}$.

Complete answer:
The mass of one mole of a substance is known as the molar mass of that substance. Its SI base unit is kg/mol but it is usually expressed in g/mol. It is a bulk property of a substance, not a molecular property.
First, we need to determine the molecular mass of iron (III) oxide.
Now, the molecular mass of one mole of a compound is equal to the sum of atomic masses of all the elements present in the molecule.
We know that the atomic mass of iron (${{M}_{Fe}}$) is 55.847 g/mol and the atomic mass of oxygen (${{M}_{O}}$) is 15.999 g/mol
So, the molecular mass of one mole of $F{{e}_{2}}{{O}_{3}}$ (${{M}_{F{{e}_{2}}{{O}_{3}}}}$) is

& {{M}_{F{{e}_{2}}{{O}_{3}}}}=2\times {{M}_{Fe}}+3\times {{M}_{O}} \\\ & {{M}_{F{{e}_{2}}{{O}_{3}}}}=2\times 55.847+3\times 15.999 \\\ & {{M}_{F{{e}_{2}}{{O}_{3}}}}=159.691g/mol \\\ \end{aligned}$$ It is given to us that the mass of the sample substance is 21.6 grams. Now, the number of moles in a given sample can be given by $$n=\frac{w}{M}$$ Where n is the number of moles, w is the mass of the substance given (in grams), and M is the molar mass of the substance (in g/mol). So, the number of moles of the substance in the sample is $$\begin{aligned} & n=\frac{21.6g}{159.691g/mol} \\\ & n\cong 0.135mol \\\ \end{aligned}$$ We know that 1 mole of $F{{e}_{2}}{{O}_{3}}$ contains 2 moles of Fe and 1.5 moles of ${{O}_{2}}$. $$F{{e}_{2}}{{O}_{3}}\to 2Fe+\frac{3}{2}{{O}_{2}}$$ So, 0.135 moles of $F{{e}_{2}}{{O}_{3}}$ will contain $$\begin{aligned} & {{n}_{Fe}}=2\times 0.135mol \\\ & {{n}_{Fe}}=0.27mol \\\ \end{aligned}$$ And the mass of iron in $F{{e}_{2}}{{O}_{3}}$ will be $$\begin{aligned} & {{w}_{Fe}}={{n}_{Fe}}\times {{M}_{Fe}} \\\ & {{w}_{Fe}}=0.27\times 55.847 \\\ & {{w}_{Fe}}=40.21g \\\ \end{aligned}$$ Hence, there are 40.21 grams of iron in 21.6 g of iron (III) oxide. **Note:** It should be noted that if one mole of a substance is present, it has exactly the Avogadro number (${{N}_{A}}=6.022\times {{10}^{23}}$) of particles and the mass of one mole of a compound is equivalent to the sum of the mass of all the particles contained in one mole of a substance. This can also be used to define the molar mass of a substance.