Question
Question: How many grams of \(CS2\)are needed to produce 6 moles of sulfur dioxide? \(CS2+\,{{O}_{2\,}}\to \,C...
How many grams of CS2are needed to produce 6 moles of sulfur dioxide? CS2+O2→CO2+SO2
Solution
This question is based on the concept of basic stoichiometry and balancing of chemical equations. In this question we will firstly balance the given equation and then will perform the basic stoichiometry and unitary method.
Complete answer:
The balanced chemical reaction can be represented as CS2+3O2→CO2+2SO2
The balanced reaction tells us that for every one mole of CS2consumed, three moles of sulfur dioxide (SO2)is formed
In the question we are asked to find out the quantity of CS2required to produce 6moles of SO2
Now we know that six is three times of two
Therefore, we will multiply the above balanced reaction by 3.
By this we will get 6moles of SO2 on R.H.S of the equation. Corresponding to it on RHS we will get the moles of CS2that are required to produce6moles of sulfur dioxide.
The reaction can be written as
3CS2+9O2→3CO2+6SO2
From the above reaction we can infer that 3moles of carbon disulfide are required to produce 6moles of sulfur dioxide.
But we need to find the quantity of CS2in grams. For this we need to convert 3 moles of carbon disulfide to grams.
We know that one mole of any substances contains mass equal to its molar mass.
Therefore, if we multiply 3 moles of carbon disulfide with its molar mass, we will get the quantity of carbon disulfide in grams.
Molar mass of CS2=76.139g/mol
⇒3×76.139=228.417grams of CS2
Hence, 228.417grams of CS2are needed to produce 6moles of SO2.
Note: Stoichiometry becomes a sticking spot for many students due to some common errors. To avoid them make sure that the chemical equation is properly balanced. Determine the starting and ending points to figure out the necessary conversions. Calculate the molar masses of substances properly.