Solveeit Logo

Question

Question: How many grams of \(CS2\)are needed to produce 6 moles of sulfur dioxide? \(CS2+\,{{O}_{2\,}}\to \,C...

How many grams of CS2CS2are needed to produce 6 moles of sulfur dioxide? CS2+O2CO2+SO2CS2+\,{{O}_{2\,}}\to \,C{{O}_{2}}\,+\,S{{O}_{2}}

Explanation

Solution

This question is based on the concept of basic stoichiometry and balancing of chemical equations. In this question we will firstly balance the given equation and then will perform the basic stoichiometry and unitary method.

Complete answer:
The balanced chemical reaction can be represented as CS2+3O2CO2+2SO2C{{S}_{2}}\,+\,3{{O}_{2\,}}\to \,C{{O}_{2}}\,+\,2S{{O}_{2}}
The balanced reaction tells us that for every one mole of CS2C{{S}_{2}}consumed, three moles of sulfur dioxide (SO2)(S{{O}_{2}})is formed
In the question we are asked to find out the quantity of CS2C{{S}_{2}}required to produce 66moles of SO2S{{O}_{2}}
Now we know that six is three times of two
Therefore, we will multiply the above balanced reaction by 33.
By this we will get 66moles of SO2S{{O}_{2}} on R.H.S of the equation. Corresponding to it on RHS we will get the moles of CS2C{{S}_{2}}that are required to produce66moles of sulfur dioxide.
The reaction can be written as
3CS2+9O23CO2+6SO23C{{S}_{2}}\,+\,9{{O}_{2\,}}\to \,3C{{O}_{2}}+\,6S{{O}_{2}}
From the above reaction we can infer that 33moles of carbon disulfide are required to produce 66moles of sulfur dioxide.
But we need to find the quantity of CS2C{{S}_{2}}in grams. For this we need to convert 33 moles of carbon disulfide to grams.
We know that one mole of any substances contains mass equal to its molar mass.
Therefore, if we multiply 3 moles of carbon disulfide with its molar mass, we will get the quantity of carbon disulfide in grams.
Molar mass of CS2=76.139C{{S}_{2}}\,=\,76.139\,g/mol
3×76.139=228.417\Rightarrow \,3\,\times \,76.139\,=\,228.417grams of CS2C{{S}_{2}}
Hence, 228.417228.417grams of CS2C{{S}_{2}}are needed to produce 66moles of SO2S{{O}_{2}}.

Note: Stoichiometry becomes a sticking spot for many students due to some common errors. To avoid them make sure that the chemical equation is properly balanced. Determine the starting and ending points to figure out the necessary conversions. Calculate the molar masses of substances properly.