Question
Question: How many grams of calcium carbonate, \[CaC{{O}_{3}}\] contain \(48\) grams of oxygen atoms?...
How many grams of calcium carbonate, CaCO3 contain 48 grams of oxygen atoms?
Solution
We know that to answer this question we need to recall the concept of the law of constants proportion. Also the law of constant proportion states that the chemical compound is made of an element which is always present during fixed ratio by mass. These imply any pure sample of compound regardless of a source which will always contain equivalent elements which results that are present within the same ratio by masses.
Complete step-by-step answer:
Since the mass percentage of Ca in a CaCO3 = 40. By using a law of constant proportion which is true sometime and it is called Proust's law which states that the given compound contains its component element in fixed ratio as well as it doesn't depend upon its source with method of preparation.
Calcium carbonate is a chemical compound with formula CaCO3. It is a common substance found in rocks as mineral calcite as well as aragonite. Similarly, we have 48grams of Oxygen in and so that we know that there are 3 oxygen atoms in CaCO3….by dividing 48 by 3 which is 16 and mass of oxygen is 16 too.
Like that we know Carbon is around 12 grams
By summing Calcium + Carbon + Oxygen ×3………………( here we have multiplied by 3since CaCO3 has 3 molecules)
⇒ 40 + 12 + (16×3)
⇒ 40 + 12 + 48
⇒ 100 grams
Therefore, 100 grams of calcium carbonate, CaCO3 contain 48 grams of oxygen atom.
Note: Note that the Law of Conservation of the Mass that is the mass of a closed system will always stay constant over time no matter the process which is occurring inside the system. Mass can not be made but it's often rearranged as we are altered into differing types of a particle.