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Question: How many gram of dibasic acid (molecular weight 200) should be present in 100 mL of the aqueous solu...

How many gram of dibasic acid (molecular weight 200) should be present in 100 mL of the aqueous solution to give 0.10.1normality?

A

1g

B

2g

C

10g

D

20g

Answer

1g

Explanation

Solution

Equivalent weight = molecular weight  basicity = \frac { \text { molecular weight } } { \text { basicity } }

=2002=100= \frac { 200 } { 2 } = 100

Normality

= weight  equiva ln et weight ×1000 volume of solution (in mL ) = \frac { \text { weight } } { \text { equiva ln et weight } } \times \frac { 1000 } { \text { volume of solution (in } \mathrm { mL } \text { ) } } weight of solute =0.1×100×1001000=1 g= \frac { 0.1 \times 100 \times 100 } { 1000 } = 1 \mathrm {~g}