Question

How many gram equivalents of NaOH are required to neutralize 25 $cm^3$ of decinormal HCl solution ?

• A. 0.00125
• B. 0.0025
• C. 0.005
• D. 0.025

Answer 1

Answer: (B)

0.0025

Answer 2

$1000\,cm^{3}$ of $0.1\,N\,Cl$ neutralizes $0.1\, g$ e of $NaOH$ $25\, cm^{3}$ of $0.1\,N\,HCl$ neutralizes $NaOH$ $=\frac{0.1}{1000} \times 25$ $=0.0025\,g$ eq