Question

How many gram-equivalents of $NaOH$ are required to neutralise $25 \,cm^3$ of a decinormal $HCl$ solution?

• A. $0.00125$
• B. $0.0025$
• C. $0.0050$
• D. $0.025$

Answer 1

Answer: (B)

$0.0025$

Answer 2

For acid-base reactions,

$\underset{(HCl)}{\text{g-equivalent of acid}}$ $\underset{(NaOH)} {\text{=g-equivalent of base}}$
$\therefore$ g -equivalent of acid $=\left(25 \times 10^{-3}\right) dm ^{3} \times \frac{1}{10}$
$=25 \times 10^{-4}$

or $=0.0025$
$=g$ -equivalent of $NaOH$