Question
Question: How many gold atoms are contained in \(0.650\) grams of gold?...
How many gold atoms are contained in 0.650 grams of gold?
Solution
We will use the Avogadro number to determine the number of atoms in the given gram. For this first, we have to calculate the moles of gold in the given gram. For this, we will use the mole formula. Then by using the Avogadro number we will determine the numbers of atoms.
Complete solution:
We will use the mole formula to determine the number of moles of gold as follows:
mole = molarmassmass
The molar mass of gold is 196.96 g/mol.
On substituting 0.650 grams for the mass of gold and 196.96for molar mass of gold,
mole = 196.960.650
mole = 3.3×10−3
So, the moles of the gold is3.3×10−3.
According to the Avogadro number,
One mole of any substance =6.02×1023 atoms
So,
One mole =6.02×1023 atoms of gold
So, 3.3×10−3moles of gold will have,
3.3×10−3mole of gold =6.02×1023×3.3×10−3 atoms of gold
=1.98×1021 atoms of gold
So, 1.98×1021 atoms of gold are present in 0.650 g of gold.
Therefore, 1.98×1021 atoms is the correct answer.
Note: The number of atoms present in 12g of carbon-12 is known as one mole. In the case of monoatomic, one mole of a substance contains an Avogadro number of atoms. Gold is monoatomic. In molecules, the subscript after each atom represents the numbers of that atom. The superscript represents the charge of an ion not the number of that ion. We can also determine the total number of molecules and ions by using the Avogadro number. For this, we have to multiply the Avogadro with a total number of molecules or ions.