Question

How many g of dibasic acid (mol. wt. 200) should be present in 100 mL of the aqueous solution to give 0.1 normality ?

• A. 1 g
• B. 2 g
• C. 10 g
• D. 20 g

Answer 1

Answer: (A)

1 g

Answer 2

Equivalent weight of dibasic acid
$=\frac{ mol , \text { wt. }}{2}=\frac{200}{2}=100$
Strength $=0.1 \,N , m =?, V =100\, ml .$
From, $m =\frac{ E V N }{1000}$
$=\frac{100 \times 100 \times 0.1}{1000}=1\, g$