Question
Question: How many formula units make up \[37.4g\] of magnesium chloride (\[MgC{l_2}\])?...
How many formula units make up 37.4g of magnesium chloride (MgCl2)?
Solution
A mole of a substance contains 6.023×1023 formula units of that substance. This unit is referred to as the Avogadro’s constant. The unit is expressed as g/mol.
Complete step by step answer:
The given question is based on the mole concept of a substance. The term mole is related to the amount of substance present in the compound. By definition a mole is the amount of substance which contains 6.023×1023number of elementary particles. The elementary particles are ions, atoms or molecules.
A mole is also defined as the amount of substance which is equal to the molar mass of that substance. Thus mole is represented as the ratio of amount of substance and the molecular weight or molar mass of that substance.
mole=molar mass of substanceamount of substance
For determination of the formula units of a substance, so we need to evaluate the moles of the substance in consideration. The given compound is magnesium chloride. The molar mass of magnesium chloride = atomic mass of Mg + 2 × atomic mass of Cl
=24.305+2×35.453=95.211g/mol.
The compound magnesium chloride is given as 37.4g. So the moles of magnesium chloride is
=95.211g/mol37.4g=0.393moles.
So the sample contains 0.393moles of magnesium chloride.
Now according to mole concept one mole of magnesium chloride contains 6.023×1023 formula units. Thus the formula units present in 0.393moles of magnesium chloride is
=0.393×6.023×1023=2.37×1023 formula units.
Hence 2.37×1023 unitsmake up 37.4g of magnesium chloride (MgCl2).
Note: The mole of any substance is used to express the exact amount of substance. It is used in determining the amounts of other reagents used for a reaction. It is also used to determine the theoretical yield and the obtained yield in a reaction.