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Question: How many faradays are required to reduce one mol of \(\text{Mn}\text{O}_{4}¯\text{toM}\text{n}^{2 +}...

How many faradays are required to reduce one mol of MnO4¯toMn2+\text{Mn}\text{O}_{4}¯\text{toM}\text{n}^{2 +} -

A

1

B

2

C

3

D

5

Answer

5

Explanation

Solution

8H+ + 5e– + MnO4– \longrightarrow Mn+2 + 4H2O (1 mole)

5 mole e– = 5 Faraday.