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Question

Quantitative Aptitude Question on Square and Square Roots

How many factors of 24×35×1042^4\times3^5\times10^4 are perfect squares which are greater than 1 ?

A

44

B

38

C

45

D

22

Answer

44

Explanation

Solution

24×35×104=28×35×542^4×3^5×10^4=2^8×3^5×5^4
To obtain perfect squares, we should consider solely the even powers of the prime factors within the number.
There are five possible ways to utilize the prime factor 2i.e, 20,22,24,26,282^0, 2^2, 2^4, 2^6, 2^8
There are three possible ways to utilize the prime factor 3 i.e. 30,32,343^0, 3^2, 3^4
There are three possible ways to utilize the prime factor 5 i.e. 50,52,545^0, 5^2, 5^4
Hence, the overall count of factors that qualify as perfect squares =5×3×3=45= 5×3×3=45
However, this count encompasses the number 1. Therefore, when excluding 1, the desired quantity is 451=44.45 - 1 = 44.