Question

How many even numbers of 3 different digits can be formed from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9 (repetition is not allowed)

• A. 224
• B. 280
• C. 324
• D. None of these

Answer 1

Answer: (A)

224

Answer 2

The number will be even if last digit is 2, 4, 6 or 8 i.e., the last digit can be filled in 4 ways and remaining two digits can be filled in $8P_{2}$ ways. Hence required number of numbers are $8P_{2} \times 4 = 224$.