Question

How many electrons go on each ring according to the Bohr model?

Answer 1

The Bohr model states that the number of the electrons on each ring of an atom is filled up according to the number of elements or atoms present in the rows or we can say in the periods of periodic table.

Complete step by step answer:
As we know that according to the Bohr model the number of electrons filled in the successive rings of the atom is equal to the number of atoms present in the respective manner in the successive rows of the periodic table.
-In the periodic table two elements i.e. Hydrogen ({\text{H & He}}) are present in the first row then according to Bohr model two electrons will go on the first orbital ring of the atom.
-In the second row of periodic table eight atoms (${\text{Li,Be,B,C,N,O,F,Ne}}$) are present then in the second orbital ring of the atom eight electrons will go.
-Similarly in the third row of periodic table eight atoms (${\text{Na, Mg, Al, Si, P, S, Cl, Ar}}$) are present then in the third orbital ring of the atom also, eights electrons will go.
-As we move down in the periodic table eighteen atoms are present in the fourth and fifth row also then in the 4th and 5th ring eighteen electrons will go.
Hence, according to the Bohr model $2, 8, 8, 18, 18$, so on electrons will go on each ring of an atom.

Note: Some of you may think that usually why we use the concept of Bohr model till $2, 8, 8$ only; so the reason is that for most of the chemist configuration of the 4th and 5th ring was not proved correct during their experiments. That’s why we use it till 3rd ring only.