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Question: How many electronic charges form 1 coulomb? \[ A.{\text{ }}9.1 \times {10^{ - 31}} \\\ B.{...

How many electronic charges form 1 coulomb?

A. 9.1×1031 B. 1.6×1018 C. 62.5×1017 D. 1.76×1011  A.{\text{ }}9.1 \times {10^{ - 31}} \\\ B.{\text{ }}1.6 \times {10^{18}} \\\ C.{\text{ }}62.5 \times {10^{17}} \\\ D.{\text{ }}1.76 \times {10^{11}} \\\
Explanation

Solution

Hint- In order to find the number of electronic charges we will use the charge of electron which is given as e=1.6×1019Ce = 1.6 \times {10^{ - 19}}C and we will proceed further by using the formula relating the total charge and the number of charged particles.

Formula used- q=neq = ne

Complete step-by-step answer:

We know the charge is negative on an electron, so it is negative e=1.6×1019Ce = 1.6 \times {10^{ - 19}}C
We need to quantify the number of electrons which constitute one charging coulomb.
Total charge required 1 Coulomb.
Therefore q=1Cq = 1C
We know the formula relating total charge and the number of charged particle is given as:
q=ne n=qe.........(1)  q = ne \\\ \Rightarrow n = \dfrac{q}{e}.........(1) \\\
Where q is the net charge, n is the number of charged particles and e is the charge of each particle.
Substituting the values in equation (1) we get:

n=qe n=1C1.6×1019C n=1×10191.6 n=100×10171.6 n=62.5×1017  \because n = \dfrac{q}{e} \\\ \Rightarrow n = \dfrac{{1C}}{{1.6 \times {{10}^{ - 19}}C}} \\\ \Rightarrow n = \dfrac{{1 \times {{10}^{19}}}}{{1.6}} \\\ \Rightarrow n = \dfrac{{100 \times {{10}^{17}}}}{{1.6}} \\\ \Rightarrow n = 62.5 \times {10^{17}} \\\

Hence, 62.5×101762.5 \times {10^{17}} electronic charges form 1 coulomb.
So, the correct answer is option C.

Note- One coulomb is equal to the amount of charge from a current of one ampere flowing for one second. One coulomb is equal to the charge on 62.5×101762.5 \times {10^{17}} electrons. The charge on 1 electron is e=1.6×1019Ce = 1.6 \times {10^{ - 19}}C of negative charge. Students must remember the value of charge present on one electron to solve such problems. Also e=1.6×1019Ce = 1.6 \times {10^{ - 19}}C of positive charge is present on one proton.