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Question: How many different wavelengths may be observed in the spectrum from a hydrogen sample if the atoms a...

How many different wavelengths may be observed in the spectrum from a hydrogen sample if the atoms are excited to state with principal quantum number nn ?

Explanation

Solution

When hydrogen atom is energetically excited then the electromagnetic radiations came out of it in a number of different ranges of their difference in wavelength, this collection of electromagnetic radiations in s spectrum is a evidence to show the quantization electronic nature of atoms, and these spectrum are known as Hydrogen spectrum.

Complete step by step answer:
Let us first understand the mechanism of the hydrogen spectrum in brief. When a hydrogen atom is energized enough then electrons get sufficient energy to jump from higher principal quantum state to lower quantum state and hence they release a significant amount of electromagnetic radiation of different wavelengths.

These wavelength are generally measured by a famous Rydberg formula which is mathematically represented as:
1λ=RHZ2[1n121n22]\dfrac{1}{\lambda } = {R_H}{Z^2}[\dfrac{1}{{{n_1}^2}} - \dfrac{1}{{{n_2}^2}}]
Where, λ\lambda is the wavelength of the emitted electromagnetic radiation.
ZZ Is the atomic number of atoms, for hydrogen atoms it is equal to one.
RH=1.0967m1{R_H} = 1.0967{m^{ - 1}} It’s known as Rydberg constant.
n1{n_1} Is the lower principal state while n2{n_2} is the higher principal state.
Now, Total number of transitions which can occur if atoms are excited with a principal quantum number nn can be calculated as:
N=(n1)+(n2)+....+3+2+1N = (n - 1) + (n - 2) + .... + 3 + 2 + 1
N=(n1)2(n)\Rightarrow N = \dfrac{{(n - 1)}}{2}(n)
N=n(n1)2\therefore N = \dfrac{{n(n - 1)}}{2}

Hence, the total number of different wavelengths can occur if an atom is excited with a principal quantum number nn will be N=n(n1)2N = \dfrac{{n(n - 1)}}{2}.

Note: It should be remembered that the highest quantum state from which the electron can jump to its lower quantum state is taken as nn . And from this higher state electrons can jump into lower states starting from (n1)(n - 1) up to 11 and these total number of ways are the only total possibility of different wavelengths which may occur during the excitation of hydrogen atoms.