Question
Question: How many different signals can be made by \[5\] flags from \[8\] flags of different colours? A) \[...
How many different signals can be made by 5 flags from 8 flags of different colours?
A) 10
B) 6720
C) 20
D) None of these
Solution
We are provided with 8 flags of different colours and 5 flags. We need to find the total number of signals that can be made by the number of arrangements of 8 flags by taking 5 flags at a time. Arranging things is called permutation, thus we can clearly say that the given question is based on the topic “permutation”. Here we have to arrange 8 flags taken 5 flags at a time which is equivalent to filling 8 flags placed out of 5 flags. For that we have the formula of permutation: nPr.
Complete step by step answer:
We have been told that there are 8 flags of different colours by taking 5 flags at a time. Thus the total number of flags n=8 and flags to be taken at a time r=5. By applying the permutation formula =nPr
=8P5
By applying in permutation,
=(8−5)!8!
Subtracting the values in denominator,
=3!8!
Expanding the factorial,
=3×2×18×7×6×5×4×3×2×1
3,2,1 in both the numerator and the denominator will get cancel,
=8×7×6×5×4
By multiplying all the terms we will get,
=6720.
Therefore the required number of signals can be made by 5 flags from 8 flags of different colours is 6720. Hence, option (B) is correct.
Note:
Each of the different arrangements which can be made by taking some or all of a number of things at a time is called permutation. The number of permutation without any repetition states that arranging n objects taken r at a time is equivalent to filling r places out of n things =n(n−1)(n−2)...(n−r−1) ways =(n−r)!n!=nPr. We can also say that, nPr=n(n−1)(n−2)...(n−r+1), thus, 8P5=8×7×6×5×4=6720.
Thus we can say that the permutation concerns both the selection and the arrangement of the selected things in all possible ways.