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Question

Question: How many different signals can be made by \[5\] flags from \[8\] flags of different colours? A) \[...

How many different signals can be made by 55 flags from 88 flags of different colours?
A) 1010
B) 67206720
C) 2020
D) None of these

Explanation

Solution

We are provided with 88 flags of different colours and 55 flags. We need to find the total number of signals that can be made by the number of arrangements of 88 flags by taking 55 flags at a time. Arranging things is called permutation, thus we can clearly say that the given question is based on the topic “permutation”. Here we have to arrange 88 flags taken 55 flags at a time which is equivalent to filling 88 flags placed out of 55 flags. For that we have the formula of permutation: nPr^n{P_r}.

Complete step by step answer:
We have been told that there are 88 flags of different colours by taking 55 flags at a time. Thus the total number of flags n=8n = 8 and flags to be taken at a time r=5r = 5. By applying the permutation formula =nPr{ = ^n}{P_r}
=8P5{ = ^8}{P_5}
By applying in permutation,
=8!(85)!= \dfrac{{8!}}{{(8 - 5)!}}
Subtracting the values in denominator,
=8!3!= \dfrac{{8!}}{{3!}}
Expanding the factorial,
=8×7×6×5×4×3×2×13×2×1= \dfrac{{8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}}{{3 \times 2 \times 1}}
3,2,13,2,1 in both the numerator and the denominator will get cancel,
=8×7×6×5×4= 8 \times 7 \times 6 \times 5 \times 4
By multiplying all the terms we will get,
=6720= 6720.
Therefore the required number of signals can be made by 55 flags from 88 flags of different colours is 67206720. Hence, option (B) is correct.

Note:
Each of the different arrangements which can be made by taking some or all of a number of things at a time is called permutation. The number of permutation without any repetition states that arranging nn objects taken rr at a time is equivalent to filling rr places out of nn things =n(n1)(n2)...(nr1) = n(n - 1)(n - 2)...(n - \overline {r - 1} ) ways =n!(nr)!=nPr = \dfrac{{n!}}{{(n - r)!}}{ = ^n}{P_r}. We can also say that, nPr=n(n1)(n2)...(nr+1)^n{P_r} = n(n - 1)(n - 2)...(n - r + 1), thus, 8P5=8×7×6×5×4=6720^8{P_5} = 8 \times 7 \times 6 \times 5 \times 4 = 6720.
Thus we can say that the permutation concerns both the selection and the arrangement of the selected things in all possible ways.