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Question

Question: How many different nine digit number can be formed from the digits of the number 223355888 by rearra...

How many different nine digit number can be formed from the digits of the number 223355888 by rearrangement of the digits so that the odd digits occupy even places ?

A

16

B

36

C

60

D

180

Answer

60

Explanation

Solution

Total ways = 4!2!2!×5!2!3!=60\frac { 4 ! } { 2 ! 2 ! } \times \frac { 5 ! } { 2 ! 3 ! } = 60