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Question: How many different 4-persons committees can be chosen from the 100 members of the Senate? A. 25 ...

How many different 4-persons committees can be chosen from the 100 members of the Senate?
A. 25
B. 400
C. 3,921,225
D. 94,109,400

Explanation

Solution

Here, we can use combination rules and formulas, as we have to choose 4 different persons from 100 persons. Apply the combination formula, and simplify to get the answer.

Complete step by step answer:
Given, total number of members = 100
Number of members in committee = 4
Choose 4 different persons out of 100 is given as 100C4{}^{100}{C_4}
[Combination Formula: If are choosing r items out of total n items, then it can be done in nCr{}^n{C_r}ways]
Here, n = 100, r = 4
So, total number of ways
= nCr=100C4=100!4!(1004)!=100!4!96!{}^n{C_r} = {}^{100}{C_4} = \dfrac{{100!}}{{4!(100 - 4)!}} = \dfrac{{100!}}{{4!96!}}
100! = 100 × 99 × 98 × 97 × 96 × 95 × 94 × …× 3 × 2 × 1
96! = 96 × 95 × 94 × …× 3 × 2 × 1
4! = 4 × 3 × 2 × 1
Putting values,
100!4!96!=100×99×98×974×3×2×1=25×33×49×97=3921225\dfrac{{100!}}{{4!96!}} = \dfrac{{100 \times 99 \times 98 \times 97}}{{4 \times 3 \times 2 \times 1}} = 25 \times 33 \times 49 \times 97 = 3921225

Total number of different 4-person committees can be chosen from the 100 members of the Senate is 3,921,225.Hence, option (C) is correct.

Note:
In these types of questions, first check whether a question is asked about combination or permutation. Permutation means arrangement of things, and combination means taking a particular number of items at a time (arrangement does not matter in combination). Then apply the proper formula as required i.e. combination or permutation. Also, if you get a factorial of a large number, never find the value of that factorial. Cancel the two factorials using proper rules. If in any case you get the final result in factorial of a large number, then leave the result in factorial form, don’t find the value.